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Scala: Project Euler: Problem 8

November 26th, 2009

Problem:
Discover the largest product of five consecutive digits in the 1000-digit number.

object Problem8 {

    def main(args: Array[String]) :Unit = {
        println(solve(numberStr))
    }

    val numberStr = "7316717653133062491922511967442657474235534919493496983520312774506326239578318016984801869478851843858615607891129494954595017379583319528532088055111254069874715852386305071569329096329522744304355766896648950445244523161731856403098711121722383113622298934233803081353362766142828064444866452387493035890729629049156044077239071381051585930796086670172427121883998797908792274921901699720888093776657273330010533678812202354218097512545405947522435258490771167055601360483958644670632441572215539753697817977846174064955149290862569321978468622482839722413756570560574902614079729686524145351004748216637048440319989000889524345065854122758866688116427171479924442928230863465674813919123162824586178664583591245665294765456828489128831426076900422421902267105562632111110937054421750694165896040807198403850962455444362981230987879927244284909188845801561660979191338754992005240636899125607176060588611646710940507754100225698315520005593572972571636269561882670428252483600823257530420752963450"

    def solve(number:String) : Int = {
        val number1 = number
        val number2 = number1.substring(1);
        val number3 = number2.substring(1);
        val number4 = number3.substring(1);
        val number5 = number4.substring(1);

        var max = 0
        var i = 0
        while(i < numberStr.length - 5)
        {
            val n1 = Integer.parseInt(number1(i).toString)
            val n2 = Integer.parseInt(number2(i).toString)
            val n3 = Integer.parseInt(number3(i).toString)
            val n4 = Integer.parseInt(number4(i).toString)
            val n5 = Integer.parseInt(number5(i).toString)
            val product = n1 * n2 * n3 * n4 * n5
            if(product == Math.pow(9, 5)) return product
            if(product > max) {
                println(n1 + "," + n2 + "," + n3 + "," + n4 + "," + n5)
                max = product
            }
            i += 1
        }
        return max
    }
}

scala

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